Compound Interest Calculator (2024)

Calculator Use

The compound interest calculator lets you see how your money can grow using interest compounding.

Calculate compound interest on an investment, 401K or savings account with annual, quarterly, daily or continuous compounding.

We provide answers to your compound interest calculations and show you the steps to find the answer. You can also experiment with the calculator to see how different interest rates or loan lengths can affect how much you'll pay in compounded interest on a loan.

Read further below for additional compound interest formulas to find principal, interest rates or final investment value. We also show you how to calculate continuous compounding with the formula A = Pe^rt.

The Compound Interest Formula

This calculator uses the compound interest formula to find principal plus interest. It uses this same formula to solve for principal, rate or time given the other known values. You can also use this formula to set up a compound interest calculator in Excel®1.

A = P(1 + r/n)nt

In the formula

  • A = Accrued amount (principal + interest)
  • P = Principal amount
  • r = Annual nominal interest rate as a decimal
  • R = Annual nominal interest rate as a percent
  • r = R/100
  • n = number of compounding periods per unit of time
  • t = time in decimal years; e.g., 6 months is calculated as 0.5 years. Divide your partial year number of months by 12 to get the decimal years.
  • I = Interest amount
  • ln = natural logarithm, used in formulas below

Compound Interest Formulas Used in This Calculator

The basic compound interest formula A = P(1 + r/n)nt can be used to find any of the other variables. The tables below show the compound interest formula rewritten so the unknown variable is isolated on the left side of the equation.

Compound Interest Formulas

Calculation

Formula

Calculate accrued amount
Principal + Interest

A = P(1 + r/n)nt

Calculate principal amount
Solve for P in terms of A

P = A / (1 + r/n)nt

Calculate principal amount
Solve for P in terms of I

P = I / ((1 + r/n)nt - 1)

Calculate rate of interest
As a decimal

r = n((A/P)1/nt - 1)

Calculate time
Solve for t
ln is the natural logarithm

t = ln(A/P) / n(ln(1 + r/n)), then also
t = (ln(A) - ln(P)) / n(ln(1 + r/n))

Formulas where n = 1
(compounded once per period or unit t)

Calculation

Formula

Calculate accrued amount
Principal + Interest

A = P(1 + r)t

Calculate principal amount
Solve for P in terms of A

P = A / (1 + r)t

Calculate principal amount
Solve for P in terms of I

P = I / ((1 + r)t - 1)

Calculate rate of interest
As a decimal

r = (A/P)1/t - 1

Calculate rate of interest
As a percent

R = r * 100

Calculate time
Solve for t
ln is the natural logarithm

t = ln(A/P) / ln(1 + r), then also
t = (ln(A) - ln(P)) / ln(1 + r)

Continuous Compounding Formulas
(n → ∞)

Calculation

Formula

Calculate accrued amount
Principal + Interest

A = Pert

Calculate principal amount
Solve for P in terms of A

P = A / ert

Calculate principal amount
Solve for P in terms of I

P = I / (ert - 1)

Calculate rate of interest
As a decimal
ln is the natural logarithm

r = ln(A/P) / t

Calculate rate of interest
As a percent

R = r * 100

Calculate time
Solve for t
ln is the natural logarithm

t = ln(A/P) / r

How to Use the Compound Interest Calculator: Example

Say you have an investment account that increased from $30,000 to $33,000 over 30 months. If your local bank offers a savings account with daily compounding (365 times per year), what annual interest rate do you need to get to match the rate of return in your investment account?

In the calculator above select "Calculate Rate (R)". The calculator will use the equations: r = n((A/P)1/nt - 1) and R = r*100.

Enter:

  • Total P+I (A): $33,000
  • Principal (P): $30,000
  • Compound (n): Daily (365)
  • Time (t in years): 2.5 years (30 months equals 2.5 years)

Showing the work with the formula r = n((A/P)1/nt - 1):

\[ r = 365 \left(\left(\frac{33,000}{30,000}\right)^\frac{1}{365\times 2.5} - 1 \right) \] \[ r = 365 (1.1^\frac{1}{912.5} - 1) \] \[ r = 365 (1.1^{0.00109589} - 1) \] \[ r = 365 (1.00010445 - 1) \] \[ r = 365 (0.00010445) \] \[ r = 0.03812605 \]

\begin{align} R&= r \times 100 \\[0.5em] &= 0.03812605 \times 100 \\[0.5em] &= 3.813\% \end{align}

Your Answer: R = 3.813% per year

So you'd need to put $30,000 into a savings account that pays a rate of 3.813% per year and compounds interest daily in order to get the same return as the investment account.

How to Derive A = Pert the Continuous Compound Interest Formula

A common definition of the constant e is that:

\[ e = \lim_{m \to \infty} \left(1 + \frac{1}{m}\right)^m \]

With continuous compounding, the number of times compounding occurs per period approaches infinity or n → ∞. Then using our original equation to solve for A as n → ∞ we want to solve:

\[ A = P{(1+\frac{r}{n})}^{nt} \] \[ A = P \left( \lim_{n\rightarrow\infty} \left(1 + \frac{r}{n}\right)^{nt} \right) \]

This equation looks a little like the equation for e. To make it look more similar so we can do a substitution we introduce a variable m such that m = n/r then we also have n = mr. Note that as n approaches infinity so does m.

Replacing n in our equation with mr and cancelling r in the numerator of r/n we get:

\[ A = P \left( \lim_{m\rightarrow\infty} \left(1 + \frac{1}{m}\right)^{mrt} \right) \]

Rearranging the exponents we can write:

\[ A = P \left( \lim_{m\rightarrow\infty} \left(1 + \frac{1}{m}\right)^{m} \right)^{rt} \]

Substituting in e from our definition above:

\[ A = P(e)^{rt} \]

And finally you have your continuous compounding formula.

\[ A = Pe^{rt} \]

Excel: Calculate Compound Interest in Spreadsheets

Use the tables below to copy and paste compound interest formulas you need to make these calculations in a spreadsheet such as Microsoft Excel, Google Sheets and Apple Numbers.

To copy correctly, start your mouse outside the table upper left corner. Drag your mouse to the outside of the lower right corner. Be sure all text inside the table is selected. Using Control + C and Control + V ; Paste the copied information into cell A1 of your spreadsheet. Formulas will only work starting in A1. You can modify the formulas and formatting as you wish.

Calculate Accrued Amount (Future Value FV) using A = P(1 + r/n)^nt

In this example we start with a principal investment of 10,000 at a rate of 3% compounded quarterly (4 times a year) for 5 years. If you paste this correctly you should see the answer Accrued Amount (FV) = 11,611.84 in cell B1. Change the values in B2, B3, B4 and B5 to your specific problem.

Copy and paste this table into spreadsheets as explained in the above section.

Accrued Amount (FV) $ = ROUND(B3 * POWER(( 1 + ((B2/100)/B4)),(B4*B5)),2)
Rate % 3
Principal $ 10000
Compounding per year 4
Years 5

Calculate Rate using Rate Percent = n[ ( (A/P)^(1/nt) ) - 1] * 100

In this example we start with a principal of 10,000 with interest of 500 giving us an accrued amount of 10,500 over 2 years compounded monthly (12 times per year). If you paste this correctly you should see the answer for Rate % = 2.44 in cell B1. Change the values in B2, B3, B4 and B5 to your specific problem.

Copy and paste this table into spreadsheets as explained in the above section.

Rate % = ROUND(B4*((POWER((B2/B3),(1/(B4*B5))))-1)*100,2)
Accrued Amount $ 10500
Principal $ 10000
Compounding per year 12
Years 2

Further Reading

Tree of Math: Continuous Compounding

Wikipedia: Compound Interest

1Excel® is a registered trademark of Microsoft Corporation

Compound Interest Calculator (2024)

FAQs

How much is $1000 worth at the end of 2 years if the interest rate of 6% is compounded daily? ›

Hence, if a two-year savings account containing $1,000 pays a 6% interest rate compounded daily, it will grow to $1,127.49 at the end of two years.

How much is $10000 at 10% interest for 10 years? ›

If you invest $10,000 today at 10% interest, how much will you have in 10 years? Summary: The future value of the investment of $10000 after 10 years at 10% will be $ 25940.

What is $5000 invested for 10 years at 10 percent compounded annually? ›

Answer and Explanation:

The future value of the investment is $12,968.71. It is the accumulated value of investing $5,000 for 10 years at a rate of 10% compound interest.

How much is 3% interest on $5000? ›

For example, if you have $5,000 in an account that has a 3% interest rate, the balance will earn $150 in one year.

What will $1 000 be worth in 20 years? ›

As you will see, the future value of $1,000 over 20 years can range from $1,485.95 to $190,049.64.
Discount RatePresent ValueFuture Value
6%$1,000$3,207.14
7%$1,000$3,869.68
8%$1,000$4,660.96
9%$1,000$5,604.41
25 more rows

How long will it take for a $2000 investment to double in value? ›

The calculated value of the number of years required for the investment of $2,000 to become double in value is 9 years.

What will $10 000 be worth in 30 years? ›

Over the years, that money can really add up: If you kept that money in a retirement account over 30 years and earned that average 6% return, for example, your $10,000 would grow to more than $57,000. In reality, investment returns will vary year to year and even day to day.

Can I live off interest on a million dollars? ›

Historically, the stock market has an average annual rate of return between 10–12%. So if your $1 million is invested in good growth stock mutual funds, that means you could potentially live off of $100,000 to $120,000 each year without ever touching your one-million-dollar goose. But let's be even more conservative.

How much is $10000 for 5 years at 6 interest? ›

An investment of $10000 today invested at 6% for five years at simple interest will be $13,000.

How much money will I have if I invest 500 a month for 10 years? ›

What happens when you invest $500 a month
Rate of return10 years30 years
4%$72,000$336,500
6%$79,000$474,300
8%$86,900$679,700
10%$95,600$987,000
Nov 15, 2023

How many years will it take to double your investment of $10 000 at an interest rate of 6? ›

So, if the interest rate is 6%, you would divide 72 by 6 to get 12. This means that the investment will take about 12 years to double with a 6% fixed annual interest rate.

How much money will be in the account after 10 years if you deposit $4500 at 5 annual interest compounded quarterly? ›

11. If you deposit $4500 at 5% annual interest compounded quarterly, how much money will be in the account after 10 years? $7396.29 A Page 3 12. If you deposit $4000 into an account paying 9% annual interest compounded monthly, how long until there is $10000 in the account?

How can I double $5000 dollars? ›

To turn $5,000 into more money, explore various investment avenues like the stock market, real estate or a high-yield savings account for lower-risk growth. Investing in a small business or startup could also provide significant returns if the business is successful.

How much will 5000 be worth in 5 years? ›

The table below shows the present value (PV) of $5,000 in 5 years for interest rates from 2% to 30%. As you will see, the future value of $5,000 over 5 years can range from $5,520.40 to $18,564.65.

What is 3% interest on $300000? ›

Say you wanted to take out a 30-year, $300,000 mortgage with a 3% annual percentage rate, or APR. Plug the information into your mortgage calculator, and you'll see that your estimated monthly mortgage payment will be $1,265. You'll pay more than $155,000 in interest over the life of the loan.

How long will it take to double $1000 at 6% interest? ›

The answer is: 12 years.

What is the future value of $10000 deposit after 2 years at 6% simple interest? ›

The future value of $10,000 on deposit for 2 years at 6% simple interest is $11200.

How do you calculate interest over 2 years? ›

  1. The formula A = P(1 + r)t can be used to calculate compound interest, where A is the total amount at the end of the time period.
  2. Identify values for: P (the principal amount), r (the interest rate as a decimal) and t (the period of time).
  3. Put these values into the formula A = P(1 + r)t 3.

What is the FV of $100 in 2 years if the interest rate is 10% per year? ›

$121 is the future value of $100 in two years at 10%.

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